3.1759 \(\int \left (a+\frac{b}{x}\right )^{3/2} x^{7/2} \, dx\)

Optimal. Leaf size=74 \[ \frac{16 b^2 x^{5/2} \left (a+\frac{b}{x}\right )^{5/2}}{315 a^3}-\frac{8 b x^{7/2} \left (a+\frac{b}{x}\right )^{5/2}}{63 a^2}+\frac{2 x^{9/2} \left (a+\frac{b}{x}\right )^{5/2}}{9 a} \]

[Out]

(16*b^2*(a + b/x)^(5/2)*x^(5/2))/(315*a^3) - (8*b*(a + b/x)^(5/2)*x^(7/2))/(63*a
^2) + (2*(a + b/x)^(5/2)*x^(9/2))/(9*a)

_______________________________________________________________________________________

Rubi [A]  time = 0.0840323, antiderivative size = 74, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.118 \[ \frac{16 b^2 x^{5/2} \left (a+\frac{b}{x}\right )^{5/2}}{315 a^3}-\frac{8 b x^{7/2} \left (a+\frac{b}{x}\right )^{5/2}}{63 a^2}+\frac{2 x^{9/2} \left (a+\frac{b}{x}\right )^{5/2}}{9 a} \]

Antiderivative was successfully verified.

[In]  Int[(a + b/x)^(3/2)*x^(7/2),x]

[Out]

(16*b^2*(a + b/x)^(5/2)*x^(5/2))/(315*a^3) - (8*b*(a + b/x)^(5/2)*x^(7/2))/(63*a
^2) + (2*(a + b/x)^(5/2)*x^(9/2))/(9*a)

_______________________________________________________________________________________

Rubi in Sympy [A]  time = 6.60996, size = 63, normalized size = 0.85 \[ \frac{2 x^{\frac{9}{2}} \left (a + \frac{b}{x}\right )^{\frac{5}{2}}}{9 a} - \frac{8 b x^{\frac{7}{2}} \left (a + \frac{b}{x}\right )^{\frac{5}{2}}}{63 a^{2}} + \frac{16 b^{2} x^{\frac{5}{2}} \left (a + \frac{b}{x}\right )^{\frac{5}{2}}}{315 a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  rubi_integrate((a+b/x)**(3/2)*x**(7/2),x)

[Out]

2*x**(9/2)*(a + b/x)**(5/2)/(9*a) - 8*b*x**(7/2)*(a + b/x)**(5/2)/(63*a**2) + 16
*b**2*x**(5/2)*(a + b/x)**(5/2)/(315*a**3)

_______________________________________________________________________________________

Mathematica [A]  time = 0.0491955, size = 49, normalized size = 0.66 \[ \frac{2 \sqrt{x} \sqrt{a+\frac{b}{x}} (a x+b)^2 \left (35 a^2 x^2-20 a b x+8 b^2\right )}{315 a^3} \]

Antiderivative was successfully verified.

[In]  Integrate[(a + b/x)^(3/2)*x^(7/2),x]

[Out]

(2*Sqrt[a + b/x]*Sqrt[x]*(b + a*x)^2*(8*b^2 - 20*a*b*x + 35*a^2*x^2))/(315*a^3)

_______________________________________________________________________________________

Maple [A]  time = 0.008, size = 44, normalized size = 0.6 \[{\frac{ \left ( 2\,ax+2\,b \right ) \left ( 35\,{a}^{2}{x}^{2}-20\,abx+8\,{b}^{2} \right ) }{315\,{a}^{3}}{x}^{{\frac{3}{2}}} \left ({\frac{ax+b}{x}} \right ) ^{{\frac{3}{2}}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  int((a+b/x)^(3/2)*x^(7/2),x)

[Out]

2/315*(a*x+b)*(35*a^2*x^2-20*a*b*x+8*b^2)*x^(3/2)*((a*x+b)/x)^(3/2)/a^3

_______________________________________________________________________________________

Maxima [A]  time = 1.45053, size = 70, normalized size = 0.95 \[ \frac{2 \,{\left (35 \,{\left (a + \frac{b}{x}\right )}^{\frac{9}{2}} x^{\frac{9}{2}} - 90 \,{\left (a + \frac{b}{x}\right )}^{\frac{7}{2}} b x^{\frac{7}{2}} + 63 \,{\left (a + \frac{b}{x}\right )}^{\frac{5}{2}} b^{2} x^{\frac{5}{2}}\right )}}{315 \, a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((a + b/x)^(3/2)*x^(7/2),x, algorithm="maxima")

[Out]

2/315*(35*(a + b/x)^(9/2)*x^(9/2) - 90*(a + b/x)^(7/2)*b*x^(7/2) + 63*(a + b/x)^
(5/2)*b^2*x^(5/2))/a^3

_______________________________________________________________________________________

Fricas [A]  time = 0.235437, size = 81, normalized size = 1.09 \[ \frac{2 \,{\left (35 \, a^{4} x^{4} + 50 \, a^{3} b x^{3} + 3 \, a^{2} b^{2} x^{2} - 4 \, a b^{3} x + 8 \, b^{4}\right )} \sqrt{x} \sqrt{\frac{a x + b}{x}}}{315 \, a^{3}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((a + b/x)^(3/2)*x^(7/2),x, algorithm="fricas")

[Out]

2/315*(35*a^4*x^4 + 50*a^3*b*x^3 + 3*a^2*b^2*x^2 - 4*a*b^3*x + 8*b^4)*sqrt(x)*sq
rt((a*x + b)/x)/a^3

_______________________________________________________________________________________

Sympy [F(-1)]  time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((a+b/x)**(3/2)*x**(7/2),x)

[Out]

Timed out

_______________________________________________________________________________________

GIAC/XCAS [A]  time = 0.242122, size = 154, normalized size = 2.08 \[ -\frac{2}{105} \, b{\left (\frac{8 \, b^{\frac{7}{2}}}{a^{3}} - \frac{15 \,{\left (a x + b\right )}^{\frac{7}{2}} - 42 \,{\left (a x + b\right )}^{\frac{5}{2}} b + 35 \,{\left (a x + b\right )}^{\frac{3}{2}} b^{2}}{a^{3}}\right )}{\rm sign}\left (x\right ) + \frac{2}{315} \, a{\left (\frac{16 \, b^{\frac{9}{2}}}{a^{4}} + \frac{35 \,{\left (a x + b\right )}^{\frac{9}{2}} - 135 \,{\left (a x + b\right )}^{\frac{7}{2}} b + 189 \,{\left (a x + b\right )}^{\frac{5}{2}} b^{2} - 105 \,{\left (a x + b\right )}^{\frac{3}{2}} b^{3}}{a^{4}}\right )}{\rm sign}\left (x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]  integrate((a + b/x)^(3/2)*x^(7/2),x, algorithm="giac")

[Out]

-2/105*b*(8*b^(7/2)/a^3 - (15*(a*x + b)^(7/2) - 42*(a*x + b)^(5/2)*b + 35*(a*x +
 b)^(3/2)*b^2)/a^3)*sign(x) + 2/315*a*(16*b^(9/2)/a^4 + (35*(a*x + b)^(9/2) - 13
5*(a*x + b)^(7/2)*b + 189*(a*x + b)^(5/2)*b^2 - 105*(a*x + b)^(3/2)*b^3)/a^4)*si
gn(x)